Calculations.
1.Insensible water loss through airways.
The volume of water vapor (VH2O) lost during breathing is the difference between the water in exhaled air (VH2Oex) and inhaled air (VH2Oin).
VH2O in exhaled or inhaled air is the product of the water vapor fraction in the air (Fr; in %) and the ventilation rate (V), respectively: VH2O = V x Fr
where PH2O is water vapor partial pressure and Pb is barometric pressure.
where the subscript ex denotes expired air and the subscript in denotes inspired air.
With the use of the data shown in Table 1,
For 6 h,
2.Insensible (evaporative) water loss through skin and sweating.
Assuming that the rates of evaporating from the skin and sweating are even during day and night,1 the estimates for 6 h of sleep would be as follows.
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[1This assumption is inaccurate. Rates change during day and night with changes in activity and ambient temperatures and humidity (7).]
3.Loss of body mass.
A theoretical O2 consumption of 250 ml O2(STP)/min [where STP is standard temperature (0°C, 273 K) and pressure (760 mmHg)] was chosen as the metabolic rate during sleep. For more accurate values of BMR, calculate the predicted BMR according to your personal data. Choose any suitable empirical equation used in physiological tests such as the Schofield equation (10) or Harris-Benedict's equation (6). For the sleeping metabolic rate, you can also use the value of 4.6 or 4.2 kJ/min for males and females, respectively (1). Assuming fat is metabolized during night, use the caloric value of fat: 19.8 kJ/l O2. In such a case, the weight of O2 consumed is about the same as CO2 produced (12). (You can calculate also for carbohydrates or mean diet.)
where VO2 is O2 consumption.
Assuming 7,000 kcal (29.3 MJ) are required to lose 1 kg of body weight (11), this will bring a reduction in body weight of about
4.Gain of metabolic water.
The gain of metabolic water (H2Om) can be calculated as follows:
Assuming the fat metabolism and metabolic rate are as calculated previously (see above),